All you need is a Mac! Come on, you want one. A demo version of VoodooPad is available. Accordingly, I have written ToH in Lua to be run in VoodooPad. VoodooPad has a Lua-based extension language. I will shortly provide a version of these that uses the Tk bindings that I believe are avialable with Lua. OK, not really compelling reason for multi-core chips, but one does what one can for the industry.Īgain, this version runs on Lua, and requires VoodooPad, thus Mac OS X. Unfortunately, my brain does not shut off some times and it realised (while I was trying to sleep) that there was no real reason for only one ring to move at a time, so I was compelled to create this version (abstracting on the a class) that has parallel threads attempting to complete the task. I went on and thought why not relive the experience, but this time, with a modern PC type computer with display, keyboard and "" as the "assembler". Recently, I was teaching Excel VBA to a group of students and thought it would be fun to implement the Hanoi algorithm and use Excel graphics to show the "disks". I had two motivations: first, the recursive solution is very simple and required less coding and second, I was sick of all the buzz about "recursive languages" and how "magic" they were. Long ago, I implemented the Hanoi recursive algorithm directly in 6800uP machine language. Recursive Algorithm in 8088 Assembler and Excel VBA. Frankly speaking it is based on preprogrammed all possible positions of 3 disks. This increase minimum number of moves from 7 to 26. You can only move a disc onto an adjacent column". The CSS only Tower of Hanoi - for 3 disks only - by StuNicholls. Graphical implementation of the HT algorithm in an Excel spreadsheet.Įasy explained 3x3x3 Rubik's Cube solution for beginners with pictures and animations. Implementation of the HT algorithm in 6800 assembler and ET-3400 (Heathkit) emulator. net, 6Ī visualization based on a very simple program (non-recursive), that's demonstrated that solves the problem with the minimum number of moves.Ĭarlos de la Torre, cdelatorre at machinalis. The Towers of Chicago uses a dynamic algorithm to compute the optimal partition numbers, and then a recursive algorithm to compute the moves. Towers of Chicago - My software now displays up to 50 discs x 10 pegs. Non Iterative tower of Hanoi solution import of Hanoi links added by the visitors to TofH site New Additions by Visitors To make it a bit easier to see, here the version which only counts: let rec hanoi1 n p1 p2 p3 acc = Hanoi (n-1) p1 p3 p2 // this is where a move is hanoi (n-1) p2 p1 p3 acc In order to show this in a compact form, here a very short version of towers of hanoi (consider this a rapid prototype for your java program ) It also shows how to use the return value of the function to obtain - here the move list - in your case, your counter. This is where you should increase your move counter. Then you move p1 to p3 and then you move the rest from p2 to p3.įrom this textual description, it is obvious, that you only really make a move in the "move p1 to p3" section. In order to move the bottom most (n'th) disk from p1 to p3, you first need to move the n-1'th disk from p1 to p2 (and cleanup). ("\nNumber of disks chosen: " + NumberOfDisks) Int NumberOfDisks = Integer.parseInt(numOfDisks) String numOfDisks = JOptionPane.showInputDialog(null, "Enter a number!") ("\nNumber of Moves so far: " + Moves + "\nMove disk on Peg " + Peg1 + " to Peg " + Peg3) Īnswer(numOfDisks - 1, Peg1, Peg3, Peg2, Moves) Īnswer(numOfDisks - 1, Peg2, Peg1, Peg3, Moves) Public void Answer(int numOfDisks, String Peg1, String Peg2, String Peg3, int Moves) You can see that I have some commented out some Moves++, but wherever I place the counter it never seems to work. For example, 3 discs would take a minimum of 7 moves. So far I have gotten the correct placement of disks to work (each disk is being moved correctly), now I need to create a counter variable in order, to show how many moves it took for a certain number of disks inputted by the user. What you have to do now is move all the disks from peg 1 to peg 3, you can use peg 2 as a storage space for other disks. I am doing a Tower Of Hanoi program - there are 3 pegs and a stack of disks on peg 1 in the order of largest to smallest (largest on bottom, smallest on top).
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